Are you contemplating getting a dental implant? As you may already know, they can be an expensive operation. But, in the grand scheme of your oral health, implants are often a worthwhile investment.
One key thing that can affect how much you pay for dental implants is where you live. The costs of dental implants vary from state to state, and even amongst the cities within a state.
In this article, you’ll learn about the costs of dental implants in Indiana. If you are an Indiana resident and you are looking into dental implants, this is the article for you!
Cost Of Dental Implants In Indiana
To give you a rough estimate, a dental implant procedure in Indiana costs range between $4,800 to $5,500. But your costs may be either lower or higher than that.
On the low-end, dental implants may cost somewhere from $2,000 to $4,000. At the high-end, you might be looking at implants that cost $6,500 or more.
Let’s explore the factors that can contribute to your specific implant cost. One of which is where you live in Indiana. Because implant prices don’t just differ from state to state. Where you live in a state can make a difference too.
Let us look at the prices of dental implants in the top 10 most populated cities in Indiana.
Dental Implant Costs In 10 Indiana Cities
Here we see the costs of dental implants in the 10 most populated cities of Indiana.
| City | Cost Of A Single Implant |
| West Lafayette | $4,850 – $5,710 |
| Crown Point | $5,280 – $6,490 |
| Indianapolis | $5,020 – $5,690 |
| Greenwood | $5,590 – $6,220 |
| New Albany | $4,790 – $5,540 |
| Carmel | $4,850 – $5,710 |
| Richmond | $4,850 – $5,710 |
| Jeffersonville | $4,790 – $5,540 |
| Columbus | $4,790 – $5,540 |
| Michigan City | $5,280 – $6,490 |
As you can see, although many of these cities have similar ranges, there are a few with more affordable pricing. So, it can pay off to do a bit of research. Because you might save some money by getting your procedure done in a different city than the one where you live.
Next, let’s look at dental pricing in Indiana compared to the national average.
Indiana Operation Costs Compared To Rest of Country
Often, you’ll see that the national average for a dental implant ranges between $1,000 to $3,000 for a single implant. But this is not the whole story. That cost typically covers the implant alone. It doesn’t include anything else that goes into getting an implant. This includes the abutment and dentures or false teeth you’ll need.
After factoring in the entire cost, Indiana’s average costs align with the national average. In some Indiana cities, they are actually in a more affordable range in comparison to other states.
What Other Factors Affect The Costs Of Dental Implants In Indiana?
There are a variety of other factors that can adjust your final cost.
One of the more influential factors is the number of implants you need. As you may guess, more than one implant will cost you more. In fact, if you need implants for your entire mount, the cost can easily range from $20,000 to $50,000 or more.
Certain cases may require additional procedures such as bone grafts, and tooth extractions. This, too, drives up your costs. For example, an all-on-four/six with a fixed hybrid bridge (upper or lower jaw) may cost $27,000.
The materials your implants are made of will also affect how much you pay as will the type of implant you get (ie. All-On-4, Mini Implants).
Additionally, the longer you wait, the more your tooth, or teeth, will deteriorate. This will cause your dental implant operation to require those additional procedures and become even more expensive. That is why it is best to schedule your dental implants as soon as possible.
To learn more about how much implants cost, what factors affect the costs and some advice on how to save and pay for implants, check out this article on Dental Implant Costs Near Me.